Решение на Трета задача от Пепа Симеонова
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Към профила на Пепа Симеонова
Резултати
- 4 точки от тестове
- 0 бонус точки
- 4 точки общо
- 13 успешни тест(а)
- 7 неуспешни тест(а)
Код
Лог от изпълнението
..FF..F....F.F....FF
Failures:
1) Fifth task RationalSequence can calculate the first 28 rational numbers
Failure/Error: expect(RationalSequence.new(28).to_a).to eq %w(
expected: [(1/1), (2/1), (1/2), (1/3), (3/1), (4/1), (3/2), (2/3), (1/4), (1/5), (5/1), (6/1), (5/2), (4/3), (3/4), (2/5), (1/6), (1/7), (3/5), (5/3), (7/1), (8/1), (7/2), (5/4), (4/5), (2/7), (1/8), (1/9)]
got: [(1/1), (2/1), (1/2), (1/3), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1), (0/1), (-1/2), (2/1)]
(compared using ==)
# /tmp/d20151111-27349-1hwv0gs/spec.rb:12:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
2) Fifth task RationalSequence is properly enumerable
Failure/Error: expect(ones).to eq %w(1/1 1/2 1/3 1/4 1/5 1/6 1/7 1/8 1/9).map(&:to_r)
expected: [(1/1), (1/2), (1/3), (1/4), (1/5), (1/6), (1/7), (1/8), (1/9)]
got: [(1/1), (1/2), (1/3), (1/1), (1/1), (1/1), (1/1), (1/1)]
(compared using ==)
# /tmp/d20151111-27349-1hwv0gs/spec.rb:20:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
3) Fifth task FibonacciSequence can be used to calculate the Lucas numbers
Failure/Error: expect(FibonacciSequence.new(31, first: 2, second: 1).to_a).to eq [
expected: [2, 1, 3, 4, 7, 11, 18, 29, 47, 76, 123, 199, 322, 521, 843, 1364, 2207, 3571, 5778, 9349, 15127, 24476, 39603, 64079, 103682, 167761, 271443, 439204, 710647, 1149851, 1860498]
got: [0, 1, 1, 2, 3, 5, 8, 13, 21, 34, 55, 89, 144, 233, 377, 610, 987, 1597, 2584, 4181, 6765, 10946, 17711, 28657, 46368, 75025, 121393, 196418, 317811, 514229, 832040]
(compared using ==)
# /tmp/d20151111-27349-1hwv0gs/spec.rb:37:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
4) Fifth task DrunkenMathematician #meaningless can calculate for 0 and 1
Failure/Error: expect(DrunkenMathematician.meaningless(0)).to eq 1
TypeError:
nil can't be coerced into Fixnum
# /tmp/d20151111-27349-1hwv0gs/solution.rb:114:in `/'
# /tmp/d20151111-27349-1hwv0gs/solution.rb:114:in `meaningless'
# /tmp/d20151111-27349-1hwv0gs/spec.rb:73:in `block (4 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
5) Fifth task DrunkenMathematician #meaningless can calculate for 42
Failure/Error: expect(DrunkenMathematician.meaningless(42)).to eq Rational(1, 11)
ZeroDivisionError:
divided by 0
# /tmp/d20151111-27349-1hwv0gs/solution.rb:114:in `/'
# /tmp/d20151111-27349-1hwv0gs/solution.rb:114:in `meaningless'
# /tmp/d20151111-27349-1hwv0gs/spec.rb:82:in `block (4 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
6) Fifth task DrunkenMathematician #worthless can calculate for 8
Failure/Error: expect(DrunkenMathematician.worthless(8)).to eq expected
expected: [(1/1), (2/1), (1/2), (1/3), (3/1), (4/1), (3/2), (2/3), (1/4), (1/5), (5/1)]
got: [(1/1), (2/1), (1/2), (1/3), (1/1), (0/1), (-1/2), (2/1)]
(compared using ==)
# /tmp/d20151111-27349-1hwv0gs/spec.rb:108:in `block (4 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
7) Fifth task DrunkenMathematician #worthless can calculate for 15
Failure/Error: expect(DrunkenMathematician.worthless(15)).to eq %w(
expected: [(1/1), (2/1), (1/2), (1/3), (3/1), (4/1), (3/2), (2/3), (1/4), (1/5), (5/1), (6/1), (5/2), (4/3), (3/4), (2/5), (1/6), (1/7), (3/5), (5/3), (7/1), (8/1), (7/2), (5/4), (4/5), (2/7), (1/8), (1/9), (3/7), (7/3), (9/1), (10/1), (9/2), (8/3), (7/4), (6/5), (5/6), (4/7), (3/8), (2/9), (1/10), (1/11), (5/7), (7/5), (11/1), (12/1), (11/2), (10/3), (9/4), (8/5), (7/6), (6/7), (5/8), (4/9), (3/10), (2/11), (1/12), (1/13), (3/11), (5/9), (9/5), (11/3), (13/1), (14/1), (13/2), (11/4), (8/7), (7/8), (4/11), (2/13), (1/14), (1/15), (3/13), (5/11), (7/9), (9/7), (11/5), (13/3), (15/1), (16/1), (15/2), (14/3), (13/4), (12/5), (11/6), (10/7), (9/8), (8/9), (7/10), (6/11), (5/12), (4/13), (3/14), (2/15), (1/16), (1/17), (5/13), (7/11), (11/7), (13/5), (17/1), (18/1), (17/2), (16/3), (15/4), (14/5), (13/6), (12/7), (11/8), (10/9), (9/10), (8/11), (7/12), (6/13), (5/14), (4/15), (3/16), (2/17), (1/18), (1/19), (3/17), (7/13), (9/11), (11/9), (13/7), (17/3), (19/1), (20/1), (19/2), (17/4), (16/5), (13/8), (11/10), (10/11), (8/13), (5/16), (4/17), (2/19), (1/20), (1/21), (3/19), (5/17), (7/15), (9/13), (13/9), (15/7), (17/5), (19/3), (21/1), (22/1), (21/2), (20/3), (19/4), (18/5), (17/6), (16/7), (15/8), (14/9), (13/10), (12/11), (11/12), (10/13), (9/14), (8/15), (7/16), (6/17), (5/18), (4/19), (3/20), (2/21), (1/22), (1/23), (5/19), (7/17), (11/13), (13/11), (17/7), (19/5), (23/1), (24/1), (23/2), (22/3), (21/4), (19/6), (18/7), (17/8), (16/9), (14/11), (13/12), (12/13), (11/14), (9/16), (8/17), (7/18), (6/19), (4/21), (3/22), (2/23), (1/24), (1/25), (3/23), (5/21), (7/19), (9/17), (11/15), (15/11), (17/9), (19/7), (21/5), (23/3)]
got: [(1/1), (2/1), (1/2), (1/3), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1), (0/1), (-1/2), (2/1), (3/1), (1/1)]
(compared using ==)
# /tmp/d20151111-27349-1hwv0gs/spec.rb:112:in `block (4 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (3 levels) in <top (required)>'
# ./lib/language/ruby/run_with_timeout.rb:5:in `block (2 levels) in <top (required)>'
Finished in 0.01274 seconds
20 examples, 7 failures
Failed examples:
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:11 # Fifth task RationalSequence can calculate the first 28 rational numbers
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:18 # Fifth task RationalSequence is properly enumerable
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:36 # Fifth task FibonacciSequence can be used to calculate the Lucas numbers
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:72 # Fifth task DrunkenMathematician #meaningless can calculate for 0 and 1
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:81 # Fifth task DrunkenMathematician #meaningless can calculate for 42
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:106 # Fifth task DrunkenMathematician #worthless can calculate for 8
rspec /tmp/d20151111-27349-1hwv0gs/spec.rb:111 # Fifth task DrunkenMathematician #worthless can calculate for 15
История (1 версия и 0 коментара)
Пепа обнови решението на 26.10.2015 01:43 (преди над 9 години)